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Essay Details:
Essay text:
The air flow velocity in a 1 foot diameter duct is 2000 fpm (feet per minute).
The air velocity required to “capture” the hazardous material is 4000 fpm. The
cheapest and easiest way of obtaining the required velocity is to reduce the
diameter of the duct so that the air velocity must increase. What will the
diameter of the new duct in order to obtain the required air velocity (4000 fpm)?
( 4 marks)
Solution:
The continuity equation states that the volumetric flow rate of air is the same at each duct.
Q1=Q2
Q1= V1 A1
Q2= V2 A2
Therefore, V1 A1 = V2 A2
?d2 . 3.14*12
A1= 4 = 4 = 0...
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