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Essay text:
to indicate the number of double bonds and numbers to show their positions.
As with simple alkenes:
1. Find the longest chain containing the double bonds; the name of the parent hydrocarbon is taken from the longest continuous chain of carbon atoms containing the double bonds.
2. Number the chain, giving the double bonds the lowest possible number; use multipliers to indicate the total number of double bonds (di, tri, tetra, etc.) Recall that in constructing the name, substituents are arranged in alphabetical order, without regard for these multipliers.
3. For cycloalkenes, begin numbering at one double bond and proceed through the double bond in the direction to generate the lowest number at the first point of difference...
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