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As mentioned before the main aim of the experiment is to calculate the exact concentration of Limewater (Calcium Hydroxide solution). The information I have been provided with states that the limewater contains ?approximately' 1gdm-3. In order to calculate the exact concentration of limewater we shall assume for the time being that the mass of calcium carbonate is (approx) 1gdm-3. Now the approx moles of calcium carbonate present in the solution needed to be calculated, so the 1gdm-3 was converted into moles.
Moles = Mass Molar mass= (Ca: 40.1) + (O x 2: 32.0) + (H x 2: 2) = 74.1
Moles = 1 = 0...
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