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I ended up getting ten different combinations. The weights in Kg are listed in order of numbers not in order of weight in pairs of bales. So I knew I needed to figure out the heaviest and the lightest bales. So I switched the numbers 1-5 for the variables a-e. So a=1, b=2, c=3, d=4, and e=5. So now I am just going to mess with numbers until I find numbers that will work. The smallest combination of bales is 80 so I will divide that by 2 and I get 40 so I know the both numbers will be around 40. So I am just going to try moving the numbers around a little bit and see what I can get.
a + b
39 + 41 = 80
a + c
39 + 43 = 82
a + d
39 + 44 = 83
a + e
39 + 47 = 86
b + c
41 + 43 = 84
b + d
41 + 44 = 85
b + e
41 + 47 = 88
c + d
43 + 44 = 87
c + e
43 + 47 = 90
d + e
44 + 47 = 91
Well all of this works out and I didn't really write down my mistakes because I did most of it in my head and I didn't want to write it down so I just wrote down the right answers, but when I was doing it I just tried moving 1 of the numbers up or down depending on if the next combination was to high or low and I did this over and over until I found an answer that worked out for all of them...
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